Hi,

Assuming all children are set as assistants, and there are no invisible links or ones with IgnoreLayout enabled, you can infer that from the parity of the index of child's incoming link inside parent's OutgoingLinks collection:

bool left = parent.OutgoingLinks.IndexOf(child.IncomingLinks[0]) % 2 == 0;

I.e. TreeLayout places the first link's target (index 0) on the left, the next one on the right, left again, right again, etc.

I hope that helps,
Stoyan